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000-103 - AIX 6.1 Basic Operations - Dump Information

Vendor : IBM
Exam Code : 000-103
Exam Name : AIX 6.1 Basic Operations
Questions and Answers : 81 Q & A
Updated On : February 23, 2018
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000-103 Questions and Answers


How would an operator determine if the System Activity Report has been scheduled?

  1. Login as adm and run crontab Login as adm and run crontab ?

  2. Login as adm and run crontab Login as adm and run crontab ?

  3. Login as root and run crontab Login as root and run crontab ?

  4. Login as root and run crontab Login as root and run crontab ?

Answer: B


Which of the following commands can be used to show all disks configured on the


  1. lsdev -C disk

  2. lsdev -P disk

  3. lsdev -Cc disk

  4. lsdev -Pc disk

Answer: C


What command will allow the operator to add the current working directory to the

command search path?

  1. export PATH=pwd

  2. export PATH=$PWD

  3. export PATH=$PATH:pwd

  4. export PATH=$PATH:$PWD

Answer: C


Which of the following is a correct statement about how the user environment is

configured at login?

  1. If present, the settings in the $HOME/.profile file will override the settings in the

    /etc/profile file.

  2. If both $HOME/.profile and $HOME/.env files are present, the settings in the

    $HOME/.profile file will take precedence.

  3. The settings in the /etc/environment file are system-wide and will override user customized settings in the $HOME/.profile.

  4. The settings in the /etc/profile file will override settings in the $HOME/.profile file unless the $LOCAL_PROFILE variable is set to 'true'.

Answer: C


An operator was contacted by a user who stated that the script mkit.sh seems to be hung

and that the user needs the script stopped. The operator logged in as root and issued the command: ps-ef | grep mkit.sh. The following results were returned: user1 98342 768 0 Sep 14 - 0:00 /bin/ksh /home/user1/mkit.sh Which command would the operator issue to stop the 'mkit.sh' script?

  1. halt 768

  2. kill 768

  3. halt 98342

  4. kill 98342

Answer: D


Which of the following commands will display, in MB, the total, used, and free blocks of the currently mounted filesystems?

  1. df -m

  2. du -m

  3. df –vm

  4. du -vm

Answer: C


How can an operator temporarily gain access to the command line while in a smit session, without losing the current smit session?

  1. F2 key

  2. F6 key

  3. F8 key

  4. F9 key

Answer: D


An operator has been asked to display all users which have primary or secondary group set

to 'webadmin'. Which of the following commands will retrieve the required information?

  1. lsgroup webadmin

  2. finger -G webadmin

  3. who -group webadmin

  4. grep webadmin /etc/passwd

Answer: A


An operator is editing a file using vi. Which of the following subcommand sequences will

copy the current line plus the next 2 lines to the end of the file?

  1. yyE 3p

  2. 3yy Gp

  3. 3yy :e5pp

  4. yy :g 3p

Answer: B


Which of the following commands can an operator use to view disk performance details?

  1. topas -D

  2. topas -R

  3. topas -C

  4. topas -d

Answer: A


An operator needs to replace all the occurrences of the string '/home/user1' in the current file using vi with '/home1/user2'. Which of the following sub-commands will achieve this?

  1. :1,$ s:/home/user1:/home1/user2:g

  2. :1,$ s\/home/user1\/home1/user2\/g

  3. :1,$ s\/\/home\/user1\/\/home1\/user2\/g D. :1,$ s/\\/home\\/user1/\\/home1\\/user2/g

Answer: A


Which of the following commands can be used to locate all occurrences of a file script.sh

on a system?

  1. file -l script.sh

  2. ls -ar | grep script.sh

  3. find . -name script.sh -print

  4. find / -name script.sh -print

Answer: D


The system administrator has requested that all setuid/setgid bits be removed from

executables in application filesystem. Which command will achieve this?

  1. chmod -R o-s /application

  2. chmod -R ug-s /application

  3. chmod -R -s -o /application

  4. chmod -R -s -ug /application

Answer: B


The operator is viewing a file using 'more'. What subcommand can be used to exit before

reaching the end of the file?

  1. q

  2. :w!

  3. /quit

  4. ctrl X

Answer: A

IBM 000-103 Exam (AIX 6.1 Basic Operations) Detailed Information

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    Unformatted textual content preview: UIC PHYSICS one hundred and five Spring 2013 remaining examination UIC # Physics one hundred and five remaining examination Spring 2013 Wednesday, may also eight ultimate identify (print) _________________________________________________ FIRST identify (print) _________________________________________________ Signature: _________________________________________________________ UIN #: ___________________________________________________________ Circle Your teacher: (First class day: time) Kouznetsov (Monday: 8:00 am) Campuzano (Tuesday: 12:30 pm) Kouznetsov (Monday: 2:00 pm) Giving or receiving help in any examination is trigger for dismissal from the university. some other violation of academic honesty can have the equal effect. web page 1 of 10 UIC PHYSICS a hundred and five Spring 2013 remaining exam issue numerous option brief issue 1 short problem 2 short problem 3 brief problem four short difficulty 5 long problem total features forty 10 5 10 10 5 15 ninety five web page 2 of 10 ranking UIC PHYSICS one zero five Spring 2013 last examination assorted alternative QUESTIONS (2 facets every) clearly circle the letter of the surest answer MCQ 01: In SHM (elementary harmonic motion), it is necessary that, (A) restoring force is linear (B) the course of restoring drive is opposite to displacement (C) each (A) and (B) (D) none of the above reply (C): ∆ i.e. F is linear and its route is contrary to displacement x MCQ 02: If the amplitude of the motion of an easy harmonic oscillator is doubled, by what component does the frequency of the oscillator trade? answer (B): / i.e. the frequency is independent of the amplitude (A) 2 (B) 1 (C) 1/2 (D) 4 MCQ 03: A vertical spring has a mass striking from it, which is displaced from the equilibrium place and begins to oscillate. At what point does the system have the least knowledge power? answer (D): E = okay +U = consistent (A) at the maximum element In basic Harmonic movement, maximum pace occurs at x = 0, (B) on the lowest element (C) on the factor where the spring is unstretched i.e. at equilibrium level or place. highest velocity corresponds to maximum kinetic energy, which corresponds to (D) on the equilibrium aspect minimal talents energy. MCQ 04: Grandfather clocks are designed in a method that the load on the backside of the pendulum can also be moved up or down by way of turning a small screw. feel you've got a grandfather clock at domestic that runs fast. if you turn the adjusting screw in order to movement the weight up or down? / . So, to make the clock run slower, the load ought to circulate down (A) elevate it. answer (B): 2 (B) lower it. (C) It would not matter in case you raise or lessen the weight, provided that you displace it with the aid of the right amount. 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(A) velocity reply (B): Frequency of a wave depends upon its source, so the (B) frequency (C) wavelength frequency doesn't alternate (D) amplitude MCQ 08: An ocean wave has period four.0 s and wavelength 10 m. The wave pace is (A) 1.5 m/s reply (B): / = (10 m)/(4 s) = 2.5 m/s (B) 2.5 m/s (C) 5.0 m/s (D) 7.5 m/s MCQ 09: figure to the appropriate shows quite a lot of positions of a child in action on a swing. A video display is blowing a whistle in front of the newborn. At which position, A via E, will the newborn hear the optimum frequency for the sound of the whistle? count on that the child is relocating with SHM (elementary harmonic movement). (A) A reply (C): If the baby swings in SHM, the highest velocity is (B) B on the equilibrium aspect, point C the infant will hear the (C) C highest frequency at element C, and when the newborn is swinging (D) D towards the monitor as (E) E ′ 1 MCQ 10: The 2d harmonic of a guitar string has a frequency of one hundred sixty five Hz. If the velocity of waves on the string is a hundred and twenty m/s, what is the string’s length? reply (A): (A) 0.73 m (B) 0.79 m , the place n = 1, 2, three, … (C) 0.eighty one m n=2 / = a hundred and twenty/165 = 0.seventy three m (D) 0.eighty five m web page four of 10 UIC PHYSICS 105 Spring 2013 remaining exam MCQ 11: in case you blow throughout the open conclusion of a soda bottle and produce a tone of 250 Hz (lowest feasible frequency), what will be the frequency of the subsequent harmonic heard in case you blow a whole lot harder? (A) 375 Hz answer (D): , where n = 1, 3, 5 …, (B) 500 Hz (C) 625 Hz So, the frequency of the subsequent harmonic is 3f1 = three·250Hz = 750 Hz (D) 750 Hz MCQ 12: Two 340 Hz sound sources dealing with every different produce sound waves which shuttle at 340 m/s towards each and every different. consequently a standing wave is produced between the sources. someone stands between the sources at a particular place and detects no sounds in any respect. The adult then walks at once in opposition t probably the most sources and prevent after they hear a maximum loudness within the sound. How some distance did the person walk? (A) 0.25 m (B) 0.50 m (C) 0.seventy five m (D) 1.00 m reply (A): ∆ the gap between two nodes is ∆ /2 . / = 0.25 m ∙ MCQ 13: within the two-slit scan, for the situation of vivid fringes, the value of m = +3 corresponds to a course difference of (A) fourλ answer (B): (B) 3λ mλ = dsin , so mλ is route difference. (C) 2λ (D) 1λ MCQ 14: The diffraction pattern of a single slit is shown in the determine to the right. The point at which the route change of the severe rays (i.e. coming from the left and appropriate sides of the slit) is two wavelengths is (A) A reply (E): (B) B Diffraction minima are given by means of wsin = mλ , the place m = (C) C 1, 2, three, … So the second minimal (m = 2) corresponds (D) D to the direction difference of twoλ between the extreme rays. 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How would an observer on the earth measure the astronaut’s pulse rate? (A) it would be slower reply (A): The astronaut’s pulse would function like a clock. in view that time moves (B) it would be quicker slower in a relocating reference frame, the observer on the planet would measure a slower (C) It would not change pulse. (D) No pulse the astronaut died a long time ago MCQ 18: An arrow 30 cm lengthy is fired at very excessive speed v without delay toward a hole cylinder 30 cm lengthy (each these dimensions are measured when every is at rest). The arrow passes axially inner the cylinder. An observer relocating parallel to the cylinder in the route of the arrow at a speed of (1/2)v sees the arrow moving ahead at the equal speed he sees the cylinder moving backward. He observes that (A) the arrow is shrunken and suits inner for an speedy (B) the cylinder is shrunken and the arrow in no way matches completely internal for an immediate (C) the arrow and cylinder are unchanged and stay exactly the same dimension (D) the arrow and cylinder are both shrunken and remain the identical size answer (D): both arrow and cylinder are relocating at the same speed relative to observer, so the observer judges that both arrow and cylinder have reduced in size the same volume due to relativistic length contraction, i.e. stay the equal dimension MCQ 19: A spear is thrown at a extremely high pace. because it passes, you measure its size at one-half its typical length. From this dimension, you conclude that the relativistic mass of the moving spear should be: (A) Equal to its leisure mass answer (D): and . 2 and 2 (B) One-half its rest mass (C) One-quarter its rest mass (D) Twice its leisure mass MCQ 20: what's the ingredient ( (A) 1 (B) 2 (C) 3 (D) four reply (C): ) of a particle having a kinetic energy of 2m0c2? and web page 6 of 10 2 three UIC PHYSICS 105 Spring 2013 remaining examination short complications naturally circle the letter of the most desirable reply SP1: an easy pendulum of mass (bob) m = 0.88 kg and size L is oscillating in a aircraft a couple of vertical line as proven in the displacement-versus-time graph in the figure beneath. (a) [4 points] check the length of the pendulum. solution: 2 / . From graph T = 1 s (A) 0.25 m . ∙ = 0.248 m = 0.25 m (B) 0.50 m (C) 0.75 m (D) 1.0 m (b) [6 points] Calculate the anxiety in the string F when the bob is passing through its lowest position. solution: At lowest element (A) 1.0 N . From graph, A = 0.1 m and ω = 2/T = 6.28 s1 , the place 0.88 . . (B) 5.0 N 9.eighty one = 10 N (C) 7.5 N (D) 10 N SP2: A 5-g string that is stretched between fixed supports separated by 75.0 cm can produce frequencies of 420 Hz and 315 Hz, and not using a intermediate frequencies. (a) [5 points] what is the bottom frequency that will also be produced on the string? solution: ∆ = 420 Hz 315 Hz = one zero five Hz (A) fifty two.5 Hz (B) a hundred and five Hz (C) 125 Hz page 7 of 10 (D) 210 Hz UIC PHYSICS one hundred and five Spring 2013 remaining exam (b) [5 points] what's the anxiety within the string? solution: 2 . So, four = four · 1052 · 0.005 · 0.75 = 165 N This half usually are not graded because of a typo within the solutions (A) 1.fifty seven N (B) eighty two.7 Hz N (C) a hundred forty five Hz N (D) one hundred sixty five Hz N SP3: A French submarine and a U.S. submarine circulation towards each different during maneuvers in motionless water in the North Atlantic. The French submarine strikes at velocity vF = 50.00 km/h and the U.S. at vUS = 70.00 km/h. The French sub sends out a sonar signal (sound wave in water) at 1.000 103 Hz. Sonar waves travel at 5470 km/h. (a) [4 points] what is the sign's frequency as detected by way of the U.S. sub? answer: The source (French sub) and observer (U.S. sub) are drawing near each and every different ∙ 1 10 = 1.022 103 Hz (A) 0.9783 103 Hz (B) 1.022 103 Hz (C) 1.045 103 Hz (D) 1.067 103 Hz (b) [6 points] What frequency is detected with the aid of the the French sub in the signal mirrored returned to it by using the U.S. sub? answer: Now, the supply is the U.S. and the French sub is observer. they're drawing near every other ′ ′ ∙ 1.022 10 = 1.045 103 Hz (A) 0.9783 103 Hz (B) 1.022 103 Hz (C) 1.045 103 Hz page 8 of 10 (D) 1.067 103 Hz UIC PHYSICS 105 Spring 2013 remaining exam SP4: Two experiments, “A” and “B” are conducted one after the other using an apparatus that consists of a double slit and a single slit (no longer always in that order). Two different patterns are produced on a screen 2 m from the apparatus. The wavelength of gentle utilized in each scan is different and the scales on the diagrams are also distinctive. experiment “A” produces a 0.22 m extensive shiny yellow band (λ = 550 nm) which is twice as extensive as other vibrant bands. experiment “B” produce vibrant and dark equally-spaced purple bands (λ = 750 nm) which are separated by means of 0.025 m. (a) [5 points] establish which of the two experiments was carried out the usage of a double slit and calculate the separation between slits. answer: experiment B: For bright fringes sin . For small perspective , sin , tan tan ∆ /∆ = 750 109 · 2/0.025 = 6 105 = 60 m So, (A) 10 m (B) 30 m (C) 60 m (D) a hundred and twenty m (b) [5 points] determine which of the two experiments become conducted the usage of a single slit and calculate the width of the slit. answer: experiment A: For dark fringes sin . For m = 1, tan / . From small attitude approximation ( sin ) tan /∆ = 550 109 · 2/0.eleven = 1 105 = 10 m So, (A) 10 m (B) 30 m (C) 60 m (D) one hundred twenty m SP5 [5 points]: You were assigned the job of designing a digicam lens for a undercover agent satellite tv for pc. This satellite tv for pc will orbit the Earth at an altitude of 320 km. The digital camera is sensitive to easy with a wavelength of 650 nm. The digital camera ought to be capable of unravel objects in the world's surface that are 0.25 m aside. If the angular decision of the camera lens is restricted via diffraction, what is the minimum diameter of the lens? sin answer: 1.22 1.22 Over 200 km, the separation of two objects may also be: ∆ 1.22 (A) 0.25 m ∆ tan 1.22 =1m (B) 0.5 m (C) 1 m page 9 of 10 ∙ (D) 2 m UIC PHYSICS 105 Spring 2013 closing examination LP: As you examine this web page, a cosmic ray proton passes along the left-appropriate width of the page with relative speed v and a total power this is 2.00 times its relaxation power. in keeping with your measurements, the left-right width is 21.5 cm. (a) [5 points] what's the width based on the proton's reference body? answer: where / , is leisure energy 2 = 21.5 cm L = 10.eight cm (A) 10.8 cm (B) sixteen.1 cm (C) 21.5 cm (D) 32.3 cm (b) [5 points] How plenty time did the passage take based on your reference frame? answer: Let's locate the proton's pace. The component 2 1 1/ 1 1/4 0.866 = 2.598 108 m/s in line with your ref. frame the passage will take t = L0/v = (21.5 102)/(2.598 108) = 828 1010 s (A) 416 1012 s (B) 828 1012 s (C) 416 1010 s (D) 828 1010 s (c) [5 points] How lots time did the passage take in keeping with proton's reference body? solution: in response to proton's ref. frame the page moves with speed v tproton = L/v = (10.eight 102)/(2.598 108) = 416 1012 s (A) 416 1012 s (B) 828 1012 s (C) 416 1010 s page 10 of 10 (D) 828 1010 s ...View Full document

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